(1/3a^2)-(1/a)=(1/6a^2)

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Solution for (1/3a^2)-(1/a)=(1/6a^2) equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

(1/3)*a^2-(1/a) = (1/6)*a^2 // - (1/6)*a^2

(1/3)*a^2-((1/6)*a^2)-(1/a) = 0

(1/3)*a^2+(-1/6)*a^2-a^-1 = 0

1/6*a^2-a^-1 = 0

a^-1*(1/6*a^3-1) = 0

1/6*a^3 = 1 // : 1/6

a^3 = 6

a^3 = 6 // ^ 1/3

a = 6^(1/3)

1/a = 0

1*a^-1 = 0 // : 1

a^-1 = 0

a należy do O

a = 6^(1/3)

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